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The law for MonadAsk ask >>= \_ -> ask = ask only requires Applicative ask *> ask = ask. You can't execute effects depending on the environment, but you can compute results depending on the environment.
The law for MonadAsk
ask >>= \_ -> ask = askonly requires Applicativeask *> ask = ask. You can't execute effects depending on the environment, but you can compute results depending on the environment.