-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy pathday7_sql_practice.sql
More file actions
265 lines (207 loc) · 6.09 KB
/
day7_sql_practice.sql
File metadata and controls
265 lines (207 loc) · 6.09 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
247
248
249
250
251
252
253
254
255
256
257
258
259
260
261
262
263
264
-- ============================================================
-- 📘 DAY 7: SQL JOIN & SUBQUERY PRACTICE
-- ============================================================
-- ============================================================
-- 🟦 JOIN PRACTICE
-- ============================================================
-- ============================
-- 🔹 INNER JOIN / JOIN
-- ============================
SELECT * FROM customers c
INNER JOIN orders o
ON c.customer_id = o.customer_id;
SELECT c.customer_id, c.name, o.amount
FROM customers c
INNER JOIN orders o
ON c.customer_id = o.customer_id;
SELECT c.customer_id, c.name, o.amount
FROM customers c
JOIN orders o
ON c.customer_id = o.customer_id;
-- ============================
-- 🔹 LEFT JOIN
-- ============================
SELECT c.customer_id, c.name, o.amount
FROM customers c
LEFT JOIN orders o
ON c.customer_id = o.customer_id;
-- ============================
-- 🔹 RIGHT JOIN
-- ============================
SELECT c.customer_id, c.name, o.amount
FROM customers c
RIGHT JOIN orders o
ON c.customer_id = o.customer_id;
-- ============================
-- 🔹 FULL OUTER JOIN (MySQL via UNION)
-- ============================
SELECT *
FROM customers c
LEFT JOIN orders o
ON c.customer_id = o.customer_id
UNION
SELECT *
FROM customers c
RIGHT JOIN orders o
ON c.customer_id = o.customer_id;
SELECT c.customer_id, c.name, o.amount
FROM customers c
LEFT JOIN orders o
ON c.customer_id = o.customer_id
UNION
SELECT c.customer_id, c.name, o.amount
FROM customers c
RIGHT JOIN orders o
ON c.customer_id = o.customer_id;
-- ============================
-- 🔹 CROSS JOIN (Cartesian Product)
-- ============================
SELECT *
FROM customers c
CROSS JOIN orders o;
SELECT c.customer_id, c.name, o.amount
FROM customers c
CROSS JOIN orders o;
-- ============================
-- 🔹 SELF JOIN
-- ============================
SELECT a.customer_id, a.amount, b.customer_id
FROM orders a, orders b
WHERE a.amount != b.amount
ORDER BY a.customer_id;
SELECT a.customer_id, a.amount, b.amount
FROM orders a
JOIN orders b
ON a.amount != b.amount
ORDER BY a.customer_id;
-- ============================
-- 🔹 JOIN with Multiple Conditions
-- ============================
SELECT *
FROM student_table s
LEFT JOIN class_table c
ON s.student_id = c.class_id
AND s.enrollment_year = c.class_year;
SELECT s.student_id, CONCAT(s.first_name,' ',s.last_name) AS Full_name,
s.class_id, c.class_name, c.teacher
FROM student_table s
LEFT JOIN class_table c
ON s.student_id = c.class_id
AND s.enrollment_year = c.class_year;
SELECT *
FROM student_table s
RIGHT JOIN class_table c
ON s.student_id = c.class_id
AND s.enrollment_year = c.class_year;
SELECT s.student_id, CONCAT(s.first_name,' ',s.last_name) AS Full_name,
s.class_id, c.class_name, c.teacher
FROM student_table s
RIGHT JOIN class_table c
ON s.student_id = c.class_id
AND s.enrollment_year = c.class_year;
SELECT s.student_id, CONCAT(s.first_name,' ',s.last_name) AS Full_name,
s.class_id, c.class_name, c.teacher
FROM student_table s
JOIN class_table c
ON s.student_id = c.class_id
AND s.enrollment_year = c.class_year;
-- ============================
-- 🔹 LEFT JOIN Filter Mistake Example
-- ============================
-- ❌ WRONG: WHERE filters RIGHT table → LEFT JOIN becomes INNER JOIN
SELECT c.customer_id, c.name, o.amount
FROM customers c
LEFT JOIN orders o
ON c.customer_id = o.customer_id
WHERE amount > 300;
-- ✔ CORRECT: Filter should be in ON
SELECT c.customer_id, c.name, o.amount
FROM customers c
LEFT JOIN orders o
ON c.customer_id = o.customer_id AND amount > 300;
-- ============================================================
-- 🟦 SUBQUERY PRACTICE
-- ============================================================
-- ============================
-- 🔹 Subquery in WHERE (Most Common)
-- ============================
SELECT MIN(score) FROM movies; -- → Example: 2.2
SELECT * FROM movies
WHERE score = 2.2;
SELECT * FROM movies
WHERE score = (SELECT MIN(score) FROM movies);
SELECT * FROM movies
ORDER BY (gross - budget) DESC
LIMIT 1;
SELECT * FROM movies
WHERE (gross - budget) = (
SELECT MAX(gross - budget) FROM movies
);
SELECT COUNT(*)
FROM movies
WHERE budget > (SELECT AVG(budget) FROM movies);
SELECT * FROM movies
WHERE year = 2000
AND score = (
SELECT MAX(score) FROM movies WHERE year = 2000
);
SELECT * FROM e_details
WHERE id IN (
SELECT id FROM e_details WHERE SALARY > 3000
);
-- ============================
-- 🔹 Subquery in SELECT (Scalar Subquery)
-- ============================
SELECT name,
(votes / (SELECT SUM(votes) FROM movies) * 100) AS per_of_votes
FROM movies;
SELECT name, genre, score,
(SELECT AVG(score)
FROM movies m2
WHERE m2.genre = m1.genre) AS Avg_Score
FROM movies m1;
-- ============================
-- 🔹 Derived Table (Subquery in FROM)
-- ============================
SELECT genre, avg_rating
FROM (
SELECT rating, AVG(score) AS avg_rating
FROM movies
GROUP BY rating
) t1
JOIN movies t2;
SELECT genre, AVG(score) AS Avg_Score
FROM movies
GROUP BY genre
HAVING AVG(score) > (SELECT AVG(score) FROM movies);
-- ============================
-- 🔹 Subqueries in INSERT / UPDATE / DELETE
-- ============================
-- INSERT using Subquery
INSERT INTO details_backup
SELECT *
FROM e_details
WHERE id IN (SELECT id FROM e_details);
-- UPDATE using Subquery
UPDATE details_backup
SET SALARY = SALARY * 10
WHERE age IN (SELECT AGE FROM e_details WHERE AGE > 20);
-- DELETE using Subquery
DELETE FROM e_details
WHERE AGE IN (
SELECT AGE FROM details_backup WHERE AGE >= 25
);
-- ============================================================
-- 🎯 PRACTICE SUMMARY (DAY 7)
-- ============================================================
/*
MASTERED TODAY:
✔ INNER, LEFT, RIGHT, FULL (UNION), CROSS, SELF JOIN
✔ JOIN with multi-condition ON clause
✔ LEFT JOIN filtering correctly
✔ WHERE / SELECT / FROM Subqueries
✔ Scalar Subqueries
✔ Derived Tables
✔ UPDATE / DELETE / INSERT with Subqueries
📌 STATUS: SQL JOIN + SUBQUERY MODULE COMPLETED
*/